Uncertainty in position of a minute particle of mass 25g in space is $10^{- 5} m$ . What is the uncertainty in its velocity $(i n m s^{- 1})$ ? $(h = 6.6 \times 10^{- 34} J s$ )

2.1 \times 10^{- 34}

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0.5 \times 10^{- 34}

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2.1 \times 10^{- 28}

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0.5 \times 10^{- 23}

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Solution

The correct option is C $2.1 \times 10^{- 28}$
$m a s s = 25 g, Δ x = 10^{- 5} m$

$Δ x . m . Δ v = \frac{h}{4 π}$

$Δ v = \frac{h}{Δ x . m . 4 π}$

$Δ v = 2.1 \times 10^{- 28} m / s$
Option C is correct.

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Similar questions

Uncertainity in position of a minute particle of mass 25g in space is $10^{- 5}$ m. What is the uncertainity in its velocity (in m $s^{- 1}$ ) ? (h= 6.6 $\times$ $10^{- 34}$ Js)

Q. Uncertainty in position of a particle of 25 g in space is

10^{- 5} m

. Hence, uncertainty in velocity (m/sec) is:

[h = 6.6 \times 10^{- 34} J - S e c]

Q. Uncertainty in position of a 0.25 g particle is

10^{- 5}

m. The uncertainty in its velocity will be:-

(h = 6.6 \times 10^{- 34} J s)

Q. What will be the minimum uncertainty in velocity of a particle of mass

1.1 \times 10^{- 28}

kg if uncertainty in its position is

3 \times 10^{- 10}

cm?

(h = 6.62 \times 10^{- 34} k g m^{2} s^{- 1})

Q. The uncertainty in the momentum of an electron is

10^{- 6} k g m s^{- 1}

. What will be the uncertainty in its position? [

h = 6.6 \times - 10^{- 34} J s

]

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Uncertainty in position of a minute particle of mass 25g in space is 10−5m. What is the uncertainty in its velocity (in ms−1)? (h=6.6×10−34Js)

The correct option is C 2.1×10−28mass=25g,Δx=10−5mΔx.m.Δv=h4πΔv=hΔx.m.4πΔv=2.1×10−28 m/sOption C is correct.

Uncertainty in position of a minute particle of mass 25g in space is $10^{- 5} m$ . What is the uncertainty in its velocity $(i n m s^{- 1})$ ? $(h = 6.6 \times 10^{- 34} J s$ )

The correct option is C $2.1 \times 10^{- 28}$
$m a s s = 25 g, Δ x = 10^{- 5} m$

$Δ x . m . Δ v = \frac{h}{4 π}$

$Δ v = \frac{h}{Δ x . m . 4 π}$

$Δ v = 2.1 \times 10^{- 28} m / s$
Option C is correct.