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Question

Under identical conditions of temperature the density of a gas $$X$$ is three times that of gas $$Y$$ while molecular mass of gas $$Y$$ is twice that of $$X$$. The ratio of pressures of $$X$$ and $$Y$$ will be


A
6
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B
1/6
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C
2/3
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D
3/2
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Solution

The correct option is A $$6$$
According to the ideal gas equation
$$PV=nRT$$

Ratio of pressure,
$$\dfrac{P_1}{P_2}=\dfrac{(M_1/V_1)RT}{M_1}\times \dfrac{1}{\dfrac{(M_2/V_2)RT}{M_2}}$$

$$=\dfrac{(d_1)RT}{M_1}\times$$ $$\dfrac{1}{\dfrac{(d_2)RT}{M_2}}$$ 

$$=\dfrac{(2d_2)RT}{M_1}\times$$ $$\dfrac{1}{\dfrac{(d_2)RT}{3M_1}}=6$$ 

Option A is correct.

Chemistry

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