Question

# Under identical conditions of temperature the density of a gas $$X$$ is three times that of gas $$Y$$ while molecular mass of gas $$Y$$ is twice that of $$X$$. The ratio of pressures of $$X$$ and $$Y$$ will be

A
6
B
1/6
C
2/3
D
3/2

Solution

## The correct option is A $$6$$According to the ideal gas equation$$PV=nRT$$Ratio of pressure,$$\dfrac{P_1}{P_2}=\dfrac{(M_1/V_1)RT}{M_1}\times \dfrac{1}{\dfrac{(M_2/V_2)RT}{M_2}}$$$$=\dfrac{(d_1)RT}{M_1}\times$$ $$\dfrac{1}{\dfrac{(d_2)RT}{M_2}}$$ $$=\dfrac{(2d_2)RT}{M_1}\times$$ $$\dfrac{1}{\dfrac{(d_2)RT}{3M_1}}=6$$ Option A is correct.Chemistry

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