Question

limh→0f(2h+2+h2)−f(2)f(h−h2+1)−f(1),(given that f′(2)=6 and f′(1)=4) is equal toIs equal to  Is equal to  Is equal to 3Does not exist

Solution

The correct option is C Is equal to 3limh→0{f(2h+2+h2)−f(2)(2h+2+h2)−2.((h−h2+1)−1)f(h−h2+1)−f(1)×2h+h2(h−h2)}=f′(2)f′(1).2=6.24=3

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