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Question

limx0x2141+x2=

A
1
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B
12
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C
4
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D
14
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Solution

The correct option is D 4
limx0x2141+x2

Let (1+x2)=t4
So, x0
t1

limt1t411t
=limt1t41(t1)
=limt1(t21)(t2+1)(t1)
=limt1(t1)(t+1)(t2+1)(t1)
=limt1(t+1)(t2+1)1
=(1+1)×(12+1)=4

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