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Use thye given data to calculate the resonance energy of $$N_2O$$. $$(\Delta H_f{^o} $$ of $$N_2O=82kJ \, mol^{-1})$$  , Bond energies of NΞN, N=N,O=O and N=O bonds are 946 ,418 ,498 and 607 kj mol-1 respectively.
Choose the correct option.


A
88kJ mol1
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B
77kJ mol1
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C
-88kJmol1
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D
-77kJmol1
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Solution

The correct option is C -88kJ$$ \, mol^{-1}$$

The options given are actually part of data of que--

SO using them

The equation for the formation of one mole of N2O will be 

 NΞN (g) + ½ O=O (g) ---> N=N=O 

Calculating the  value of ΔfH0 for this reaction will be ΔfH0 = [B.E.(NΞN) + ½ B.E.(O=O)] – [B.E.(N=N) + B.E.(N=O)] 

 =[946 + ½ (498)] – [418 + 607] kj mol-1 = 170kj mol-1 

Resonance energy = Observed ΔfH0 – Calculated ΔfH0 = 82 – 170 = - 88 kj mol-1 

SO the answer is =Resonance energy =-88


Chemistry

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