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Question

Using a suitable algebraic identity, the value of 1013 is ___ .

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Solution

Using algebraic identity (a+b)3 = (a3+b3+3a2b+3ab2)

101 = (100+1)3 = (100)3 + (1)3 + 3×1002×1 + 3×100×12

= 1000000 + 1 +30000 + 300

=1030301


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