Using identities- evaluate-1-02 - 9-8

The correct option is B 9.9961.02× 9.8= 1.02 × 0.98× 10 =(1+0.02)(1 0.02) × 10 =[(1)^2 (0.02)^2]× 10 =[1 0.0004]× 10 [Using identity (a b) (a+b) = a^2 b^2] ...

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Standard IX

Mathematics

Visualising Factors of Composite Numbers

Using identit...

Question

Using identities, evaluate:
$1.02 \times 9.8$

9.996

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0.9976

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99.96

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0.09975

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Solution

The correct option is A $9.996$
$1.02 \times 9.8 = 1.02 \times 0.98 \times 10$
$= (1 + 0.02) (1 - 0.02) \times 10$
$= [(1)^{2} - (0.02)^{2}] \times 10$
$= [1 - 0.0004] \times 10$
$[U s i n g i d e n t i t y (a - b) (a + b) = a^{2} - b^{2}]$
$= 0.9996 \times 10$
$= 9.996$

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Similar questions

Q. Using identities, evaluate:

(1.02)^{2} - (0.98)^{2}

Q. Evaluate the following by using the identities:

9.7 \times 9.8

Question 86 (xiv)

Using suitable identities, evaluate the following:

$9.8 \times 10.2$

Q. Use the identity

(a + b) (a - b) = a^{2} - b^{2}

to evaluate:

9.8 \times 10.2

Q. Evaluate

(9.8)^{2}

by using the identity

(a - b)^{2} = a^{2} - 2 a b + b^{2}

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Using identities, evaluate: 1.02×9.8

The correct option is A 9.9961.02×9.8=1.02×0.98×10 =(1+0.02)(1−0.02)×10 =[(1)2−(0.02)2]×10 =[1−0.0004]×10 [Using identity (a−b)(a+b)=a2−b2] =0.9996×10 =9.996

Using identities, evaluate:
$1.02 \times 9.8$

The correct option is A $9.996$
$1.02 \times 9.8 = 1.02 \times 0.98 \times 10$
$= (1 + 0.02) (1 - 0.02) \times 10$
$= [(1)^{2} - (0.02)^{2}] \times 10$
$= [1 - 0.0004] \times 10$
$[U s i n g i d e n t i t y (a - b) (a + b) = a^{2} - b^{2}]$
$= 0.9996 \times 10$
$= 9.996$