Using prime factorization , find the HCF and LCM of $1152, 1664$
in each case , verify that $H C F \times L C M$ = product of given numbers.

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Solution

$1152 = 2^{7} \times 3^{2}$
$1664 = 2^{7} \times 13$
LCM (1152, 1664)= $2^{7} \times 3^{2} \times 13 = 14976$
HCF(1152, 1664) = $2^{7} = 128$
Verification :
$H C F \times L C M = 14976 \times 128 = 1916928$
product of given numbers = $1152 \times 1664 = 1916928$
$\Rightarrow H C F \times L C M$ = product of given numbers

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Using prime factorization , find the HCF and LCM of 1152,1664 in each case , verify that HCF×LCM = product of given numbers.

1152=27×321664=27×13LCM (1152, 1664)= 27×32×13=14976HCF(1152, 1664) = 27=128Verification : HCF×LCM=14976×128=1916928product of given numbers = 1152×1664=1916928⇒HCF×LCM= product of given numbers

Using prime factorization , find the HCF and LCM of $1152, 1664$
in each case , verify that $H C F \times L C M$ = product of given numbers.