CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Using quadratic formula, find the value of x.
 p2x2+(p2q2)xq2=0,p0


A
q2p2,1
loader
B
q2p2,1
loader
C
0,1
loader
D
q2p2,1
loader

Solution

The correct option is A q2p2,1
 We have, p2x2+(p2q2)xq2=0, p0

Comparing this equation with ax2+bx+c=0, we have,
a=p2,b=p2q2 and c=q2.

b24ac=(p2q2)24×p2×q2

              =(p2q2)2+4p2q2

              =(p2+q2)2

x=b±b24ac2a

x=(p2q2)±(p2+q2)22p2x=(p2q2)+(p2+q2)2p2 or  x=(p2q2)(p2+q2)2p2x=q2p2 or x=1

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More



footer-image