The oxidation number of each metalic element in its compound is as follows:
HAuCl4→Au has 3
Tl2O→Tl has 1
FeO→Fe has 2
Fe2O3→Fe has 3
CuI→Cu has 1
CuO→Cu has 2
MnO→Mn has 2
MnO2→Mn has 4
Final Answer: Therefore, these compounds may be represented as:
HAu(III)Cl4, Tl2(I)O, Fe(II)O, Fe2(III)O3, Cu(I)I, Cu(II)O, Mn(II)O, Mn(IV)O2