Question

# Using the measurements given in the following figure:the value of $$\displaystyle \sin \Theta = \frac{m}{13}$$value of m is

Solution

## Draw a perpendicular from D on AB to meet at AB at E. Hence, DEBC is a rectangle.Thus, $$DE = BC = 12$$In $$\triangle DBC$$,$$BD^2 = CD^2 + BC^2$$$$13^2 = 12^2 + CD^2$$$$CD^2 = 25$$$$CD = 5$$Now, $$BE = CD = 5$$Thus, $$AE = AB - BE$$$$AE = 14 - 5$$$$AE = 9$$Now, In $$\triangle DBC$$$$\sin \Phi = \frac{P}{H} = \frac{DC}{BD} = \frac{5}{13}$$Now, In $$\triangle AED$$$$\tan \Theta = \frac{DE}{AE} = \frac{9}{12} = \frac{3}{4}$$Maths

Suggest Corrections

0

Similar questions
View More

People also searched for
View More