CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Using the measures given in the figure below, find the area of □EFGH.


Solution

The given map of the plot is of a quadrilateral that can be divided in two triangles,
∆HGF and ∆HEF.

Lengths of the sides of ∆HGF are 34 m, 50 m and 52 m

Semi-perimeter of a triangle = s=a+b+c2

Semi-perimeter  =34+50+522=68 m

Area of a triangle = ss-a s-b s-c

=68 68-34 68-50 68-52=6834 18 16=665856=816 sq m
 
∴ Area of the triangle ∆HGF is 816 sq m.

Lengths of the sides of the triangle ∆HEF are 20 m, 48 m and 52 m.

Semi-perimeter of a triangle = s=a+b+c2

Semi-perimeter = 20+48+522=60 m

Area of a triangle = ss-a s-b s-c

=6060-20 60-48 60-52=60 40 12 8=230400=480
∴ Area of the triangle ∆HEF is 480 sq m.

So, the area of EFGH = A(∆HGF) + A(∆HEF)
                                                     = 816 sq m + 480 sq m =1296 sq m

Mathematics
Mathematics(2013)
Standard VIII

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image