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Question

Using (x+a)(x+b)=x2+(a+b)x+ab,find the value of
(a)103×104
(b)103×98

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Solution

(a)103×104=(100+3)×(100+4)
=1002+(3+4)×100+3×4
=10000+700+12=10,712
(b)103×98=(100+3)×(1002)
=1002+(32)×100+3×2
=10,000+1006=10,094

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