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Byju's Answer
Standard XII
Mathematics
Determinant
Value of dete...
Question
Value of determinant
∣
∣
∣
cos
50
∘
sin
10
∘
sin
50
∘
cos
10
∘
∣
∣
∣
is:
A
0
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B
1
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C
1
/
2
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D
−
1
/
2
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Solution
The correct option is
C
1
/
2
∣
∣
∣
cos
50
∘
sin
10
∘
sin
50
∘
cos
10
∘
∣
∣
∣
=
cos
50
∘
cos
10
∘
−
sin
50
∘
sin
10
∘
=
cos
(
50
∘
+
10
∘
)
=
cos
60
∘
=
1
2
So, option (c) is correct.
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0
Similar questions
Q.
(sin 40° − cos 50°) = ?
(a) sin 10°
(b) cos 10°
(c) 1
(d) 0
Q.
The value of sin 50° − sin 70° + sin 10° is equal to
(a) 1
(b) 0
(c) 1/2
(d) 2
Q.
Show that
s
i
n
10
°
−
c
o
s
10
°
s
i
n
80
°
c
o
s
80
°
=
1
Q.
Prove that:
(i) cos 10° cos 30° cos 50° cos 70° =
3
16
(ii) cos 40° cos 80° cos 160° =
-
1
8
(iii) sin 20° sin 40° sin 80° =
3
8
(iv) cos 20° cos 40° cos 80° =
1
8
(v) tan 20° tan 40° tan 60° tan 80° = 3
(vi) tan 20° tan 30° tan 40° tan 80° = 1
(vii) sin 10° sin 50° sin 60° sin 70° =
3
16
(viii) sin 20° sin 40° sin 60° sin 80° =
3
16
Q.
If
E
=
(
sin
10
0
+
cos
10
0
)
2
+
(
cos
10
0
−
sin
10
0
)
2
, then the value of
log
0.5
E
will be
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