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Question

Van't Hoff factor of $$Hg_2Cl_2$$ in its aqueous solution will be ($$Hg_2Cl_2$$ is $$80\%$$ ionized in the solution):


A
1.6
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B
2.6
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C
3.6
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D
4.6
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Solution

The correct option is B $$2.6$$
$$Hg_2Cl_2\rightleftharpoons Hg^{2+}_2 + 2Cl^-$$

Here, $$n=3$$

Now,
$$\alpha = \dfrac{i-1}{n-1}$$

$$0.8=\dfrac{i-1}{3-1}$$

$$i=2.6$$

Chemistry

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