Vapour density of PCl5 is 104-16 but when heated to 230-C its vapour density is reduced to 62- The degree dissociation of PCl5 at this temperature will be-

The correct option is D 0.68 ...

Vapour densit...

Question

Vapour density of $P C l_{5}$ is $104.16$ but when heated to $230^{\circ}$ C its vapour density is reduced to $62$ .
The degree dissociation of $P C l_{5}$ at this temperature will be:

0.68

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Solution

$P {C l}_{5} \Leftrightarrow P {C l}_{3} + P {C l}_{2}$

$Cl2PCl_5\, \rightleftharpoons\, PCl_3\, +\, Cl$
Initial $a$ 0 0
Final $a - a x$ $a x$ $a x$
$i = \frac{a - a x + a x + a x}{a} = 1 + x$

$i = \frac{n o r m a l v a p o u r d e n s i t y}{a b n o r m a l v a p o u r d e n s i t y} = \frac{104.16}{62} = 1.68$

$i=a−ax+ax+axa=1+xi=\dfrac{a-ax+ax+ax}{a}=1+x$

$⇒1+x=1.68\Rightarrow 1+x=1.68$

$⇒x=0.68\Rightarrow x=0.68$

The degree of dissociation of $P {C l}_{5}$ is 68%
Conclusion: The correct option is (D) 68%

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