1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Vapour density of PCl5 is 104.16 but when heated to 230∘C its vapour density is reduced to 62. The degree dissociation of PCl5 at this temperature will be:

A
0.68%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
68%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
46%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
64%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## PCl5⇔PCl3+PCl2 PCl5 ⇌  PCl3 + Cl2PCl_5\, \rightleftharpoons\, PCl_3\, +\, ClInitial aa 0 0 Final a−axa-axaxax axaxi=a−ax+ax+axa=1+x i=normalvapourdensityabnormalvapourdensity=104.1662=1.68 i=a−ax+ax+axa=1+xi=\dfrac{a-ax+ax+ax}{a}=1+x⇒1+x=1.68\Rightarrow 1+x=1.68⇒x=0.68\Rightarrow x=0.68The degree of dissociation of PCl5 is 68% Conclusion: The correct option is (D) 68%

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Relative Lowering of Vapour Pressure
CHEMISTRY
Watch in App
Join BYJU'S Learning Program