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Question

Vapour density of PCl5 is 104.16 but when heated to 230C its vapour density is reduced to 62.

The degree dissociation of PCl5 at this temperature will be:

A
0.68%
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B
68%
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C
46%
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D
64%
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Solution

PCl5PCl3+PCl2


PCl5 ⇌  PCl3 + Cl2PCl_5\, \rightleftharpoons\, PCl_3\, +\, Cl

Initial aaa 0 0
Final a−axa-axaaxaxaxax axaxax
i=aax+ax+axa=1+x

i=normalvapourdensityabnormalvapourdensity=104.1662=1.68

i=a−ax+ax+axa=1+xi=\dfrac{a-ax+ax+ax}{a}=1+x

⇒1+x=1.68\Rightarrow 1+x=1.681+x=1.68

⇒x=0.68\Rightarrow x=0.68x=0.68


The degree of dissociation of PCl5 is 68%

Conclusion: The correct option is (D) 68%


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