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Question

Velocity constant of a reaction at 290 K was found to 3.2×103sec1. When the temperature is raised to 310 K, it will be about:

A
6.4×103
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B
3.2×104
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C
9.6×103
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D
1.28×102
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Solution

The correct option is D 1.28×102
From the Arhenius eqn, we know that the rate of a reaction doubles for every 10 K rise in temperature.

k2k1=22k2=3.2×103×4=1.28×102sec1

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