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Question

Verify by substitution that
(i) the root of 3x − 5 = 7 is x = 4
(ii) the root of 3 + 2x = 9 is x = 3
(iii) the root of 5x − 8 = 2x − 2 is x = 2
(iv) the root of 8 − 7y = 1 is y = 1
(v) the root of z7=8 is z = 56

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Solution

(i)

3x - 5 = 7Substituting x = 4 in the given equation:L.H.S.: 3×4 -5or, 12 - 5 = 7 = R.H.S.L.H.S. = R.H.S. Hence, x = 4 is the root of the given equation.

(ii)

3 + 2x= 9Substituting x = 3 in the given equation:L.H.S.: 3 + 2×3or, 3 + 6 = 9 = R.H.S. L.H.S. = R.H.S. Hence, x = 3 is the root of the given equation.

(iii)

5x - 8 = 2x -2 Substituting x = 2 in the given equation:L.H.S.: R.H.S. :5×2- 8 = 2×2-2or, 10 - 8 = 2 = 4 -2 = 2 L.H.S. = R.H.S. Hence, x =2 is the root of the given equation.

(iv)

8 - 7y = 1 Substituting y = 1 in the given equation:L.H.S.: 8 -7×1or, 8 - 7 = 1 = R.H.S. L.H.S. = R.H.S. Hence, y =1 is the root of the given equation.

(v)

z7 = 8 Substituting z = 56 in the given equation:L.H.S.: 567 = 8 =R.H.S.L.H.S. = R.H.S. Hence, z =56 is the root of the given equation.

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