Question

Verify by the method of contradiction that $\sqrt{2}$ is irrational.

Answer 1

Let $\sqrt{2}$ is rational.

By method of contradiction

We assume $p$ is net true.

& we arrive at some result which contradiction our assumption.

We conclude that $p$ is true.

we assume that given statement is false.

$\sqrt{2}$ is not rational.

Therefore,

$\sqrt{2}$ is irrational.