Verify that $a \div (b + c) \neq (a \div b) + (a \div c)$ for each of the following values of a, b and c.
a = 12, b = - 4, c = 2

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Solution

$a = 12, b = - 4, c = 2$
$a \div (b + c) = 12 \div (- 4 + 2) = 12 \div (- 2) = - 6 (a \div b) + (a \div c) = [12 \div (- 4)] + [12 \div 2] = - 3 + 6 = 3 H e n c e, a \div (b + c) \neq (a \div b) + (a \div c)$

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Verify that a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c) for each of the following values of a, b and c.

(a) a = 12, b = −4, c = 2

(b) a = (− 10), b = 1, c = 1

Question 2(a)
Verify that $a \div (b + c) \neq (a \div b) + (a \div c)$ for each of the following values of a, b and c.
a = 12, b = - 4, c = 2

\div

+

\div

+

\div

Question 2(b)
Verify that $a \div (b + c) \neq (a \div b) + (a \div c)$ for each of the following values of a, b and c.
a = (- 10), b = 1, c = 1

(a + b + c)^{2} = a^{2} + b^{2} + c^{2} + 2 a b + 2 b c + 2 c a

a = 2

b = 4

c = 6

a = 5

b = - 2

c = 3

a = - 2

b = 3

c = - 4

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