Vijay is pushing a block with $22 N$ force and Gopal is pushing it with $10 N$ force in the opposite direction. The block moves a distance of $6.5 m$ in the same direction in which Vijay is pushing it. The work done on the block is:

$12 J$

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$90 J$

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$85 J$

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$78 J$

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Solution

The correct option is D
$78 J$

Given:
Force applied by Vijay, $F_{1} = 22 N$
Force applied by Gopal, $F_{2} = 10 N$ .
Displacement, $s = 6.5 m$

Since, both the forces are acting in the opposite directions, net force is given by:
$F = F_{1} - F_{2}$
$F = 22 - 10 = 12 N$

The work done on the block is given by the product of displacement and the net force applied on it. Hence it is given by:
$W = F \times s$
$W = 12 \times 6.5 = 78 J$

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Vijay is pushing a block with 22 N force and Gopal is pushing it with 10 N force in the opposite direction. The block moves a distance of 6.5 m in the same direction in which Vijay is pushing it. The work done on the block is:

Vijay is pushing a block with $22 N$ force and Gopal is pushing it with $10 N$ force in the opposite direction. The block moves a distance of $6.5 m$ in the same direction in which Vijay is pushing it. The work done on the block is: