Vinay is currently 5 times as old as his son. In 6 years of time Vinay will be three times as old his son will be then. What are their ages now.

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Solution

Let the age of Vinay be 5x and his son’s age = x

After 6 years their ages will be 5x + 6 and x + 6

It is given that he would be three times the age of his son

5x + 6 = 3(x + 6)

5x + 6 = 3x + 18

2x = 12, x = 6

Son’s age = 6 years

Vinay age= 5 × 6 = 30 years

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Vinay is currently 5 times as old as his son. In 6 years of time Vinay will be three times as old his son will be then. What are their ages now.

Let the age of Vinay be 5x and his son’s age = x After 6 years their ages will be 5x + 6 and x + 6 It is given that he would be three times the age of his son 5x + 6 = 3(x + 6) 5x + 6 = 3x + 18 2x = 12, x = 6 Son’s age = 6 years Vinay age= 5 × 6 = 30 years

Let the age of Vinay be 5x and his son’s age = x

After 6 years their ages will be 5x + 6 and x + 6

It is given that he would be three times the age of his son

5x + 6 = 3(x + 6)

5x + 6 = 3x + 18

2x = 12, x = 6

Son’s age = 6 years

Vinay age= 5 × 6 = 30 years