Question

The volume of ${\mathrm{O}}_2$liberated at STP by $100\mathrm{ml}$ of $10$volume ${\mathrm{H}}_2{\mathrm{O}}_2$ solution is ?

Answer 1

Step 1: Given data:

• Volume of ${\mathrm{H}}_2{\mathrm{O}}_2=100\mathrm{ml}$
• Volume strength of ${\mathrm{H}}_2{\mathrm{O}}_2=10$ volume

Step 2: Formula for calculating the volume at STP:

The volume of ${\mathrm{O}}_2$produced at STP $=$Volume strength $\times$Volume of ${\mathrm{H}}_2{\mathrm{O}}_2$

Step 3: Calculation:

The volume of ${\mathrm{O}}_2$produced at STP $=$$10\times 100$

The volume of ${\mathrm{O}}_2$produced at STP $=$$1000\mathrm{ml}$

Therefore, the volume of ${\mathrm{O}}_2$produced at STP is $1000\mathrm{ml}$.