Water and mercury are filled in two cylindrical vessels up to same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are v₁ and v₂ respectively.

v₁ = v₂.

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v₁ = 13.6 v₂.

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v₁ = v₂/13.6.

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Solution

The correct option is A
v₁ = v₂.

As clear from the Torricelli's equation that speed of Efflux = $\sqrt{2 g h}$
i.e., it is independent of density of liquid contained.

Therefore both will come out with same velocity.

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Water and mercury are filled in two cylindrical vessels upto same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are $v_{1}$ and $v_{2}$ respectively. Thus

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Water and mercury are filled in two cylindrical vessels up to same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are v₁ and v₂ respectively.

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Water and mercury are filled in two cylindrical vessels up to same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are v1 and v2 respectively.

The correct option is A v1 = v2. As clear from the Torricelli's equation that speed of Efflux = √2gh i.e., it is independent of density of liquid contained. Therefore both will come out with same velocity.

Water and mercury are filled in two cylindrical vessels up to same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are v₁ and v₂ respectively.

The correct option is A
v₁ = v₂.

As clear from the Torricelli's equation that speed of Efflux = $\sqrt{2 g h}$
i.e., it is independent of density of liquid contained.

Therefore both will come out with same velocity.