  Question

Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate (in m2) in 30 minutes, if 8 cm of standing water is needed?

A

562500  B

625500  C

526500  D

256500  Solution

The correct option is B 562500 Canal is in the shape of a cuboid, where breadth = 6 m and height = 1.5 m. Speed of water flowing through canal = 10 km/h = 10, 000 m/h i.e., length of the canal in one hour = 10, 000 m/h Volume of water flowing through canal in 1 hour =length×breadth×height=10,000×6×1.5=90,000 m3 Volume of water flowing through canal in 30 minutes =900002=45,000 m3 Given, height of the standing water = 8 cm = 0.08 m Now, volume of water in the canal = volume of area that will be irrigated i.e., volume of water in the canal = Area that will be irrigated × height of standing water ⇒45000=Area that will be irrigated×0.08⇒Area that will be irrigated       =450000.08       =562500 m2 Mathematics

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