Question

Water rises in a capillary tube up to a length 10 cm. If the tube is inclined at 45${}^o$, the length of water rises in tube will be:

• A. 10 cm
• B. 10$\sqrt{2}$ cm
• C. $\frac{10}{\sqrt{2}}cm$
• D. none

Answer 1

The correct option is B 10$\sqrt{2}$ cm

$h=10cm$
If the tube is tilted by 45${}^o$, then the length of water column will be

$l=\frac{h}{cos{45}^o}=\frac{10}{\frac{1}{\sqrt{2}}}=10\sqrt{2}cm$