Question

Water rises in a vertical capillary tube upto a length of 10 $cm$. If the tube is inclined at 45${}^o$, the length of water risen in the tube will be

• A. $10cm$
• B. $10\sqrt{2}$ $cm$
• C. $\frac{10}{\sqrt{2}}$ $cm$
• D. none of these

Answer 1

The correct option is B $10\sqrt{2}$ $cm$

As the inclination of the tube would not affect the height of water that rises in the capillary.
So, the length of water can be calculated as:
$lcos\left({45}^o\right)=h$
$\therefore l=$ $10\sqrt{2}$ cm