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Mirror Formula and Magnification

Water ( with ...

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Water ( with refractive index 4/3) in a tank is 18 cm deep.Oil of refractive index 7/4 lies on water making a convex surface of radius of curvature R=6 cm.Consider Oil to act as a thin lens.An object Sender is placed 24 cm above water surface.The location of image is at x cm above the bottom of the tank.Then x is

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Q. Water (with refractive index

= 4 / 3)

in a tank is 18 cm deep. Oil of refractive index 7/4 lies on water making a convex surface of radius of curvature

R = 6 c m

as shown. Consider oil to act as a thin lens. An object S is placed 24 cm above water surface. The location of its image is at 'x' cm above the bottom of the tank. Then x is

Q. The convex surface of a thin concavo-convex lens of glass of refractive index

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has a radius of curvature

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. The concave surface has a radius of curvature

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. The convex side is silvered and placed on a horizontal surface.
If the concave part is filled with water of refractive index

4 / 3

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. The image of a coin kept at the bottom of the vessel is thus formed

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