CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Wavelength of red light is $$7.5 \times 10^{-5}\ cm$$ and that of blue light is $$5.0 \times 10^{-5}\ cm$$. The value of $$n$$ for which $$(n+1)$$ th blue bright band coincides with $$n^{th}$$ red band, is:


A
8
loader
B
4
loader
C
2
loader
D
1
loader

Solution

The correct option is D $$2$$
Position of bright Band in YDSE.
$$y=\dfrac{nD\lambda }{d}$$
So, By given problem
$$\dfrac{n D\lambda _{R}}{d}=(n+1)\dfrac{D\lambda_{ B}}{d}$$
$$n7.5\times 10^{-5}=(n+1)5\times 10^{-5}$$
$$7.5n=5n+5$$
$$2.5n=5$$
$$n=2$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image