Question

# Wavelength of red light is $$7.5 \times 10^{-5}\ cm$$ and that of blue light is $$5.0 \times 10^{-5}\ cm$$. The value of $$n$$ for which $$(n+1)$$ th blue bright band coincides with $$n^{th}$$ red band, is:

A
8
B
4
C
2
D
1

Solution

## The correct option is D $$2$$Position of bright Band in YDSE.$$y=\dfrac{nD\lambda }{d}$$So, By given problem$$\dfrac{n D\lambda _{R}}{d}=(n+1)\dfrac{D\lambda_{ B}}{d}$$$$n7.5\times 10^{-5}=(n+1)5\times 10^{-5}$$$$7.5n=5n+5$$$$2.5n=5$$$$n=2$$Physics

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