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Question

We can’t apply rolle’s theorem on f(x) = |x| on the interval [-2, 2] because -


  1. x is not a function.

  2. f(x) = |x| is not continuous in the interval  [-2, 2]

  3. f(x) = |x |is not differentiable in the interval  (-2, 2)

  4. f(-2) f (2)


Solution

The correct option is C

f(x) = |x |is not differentiable in the interval  (-2, 2)


Let’s consider each option individually.

a. |x| is a function because the function is defined on  [-2, 2] and no x value from this interval left in the domain and there is no such x in the domain which are giving two values as output. As all the conditions for being a function is satisfied we can say it is a function.

b. f(x) = |x| is definitely continuous in the interval  [-2, 2] . We can see that very easily by making graph that there is no point where function breaks its continuity.

c. f(x) = x is not differentiable at  x = 0.

As L.H. D and R.H.D are not same. This is because the function definition on the right side of zero is y = x and on the left side it is y = -x. They give different slopes on differentiating making L.H.D and R.H.D not equal.So, we can’t apply Rolle’s theorem since f(x) is not differentiable in the given interval.

d. f(-2) =  f (2)

AS we can see  f(-2)  = |-2|   =  2 &   f(2) =   2 So both are equal.

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