What amount of oxalic acid is required to prepare 250 mL 0.1 N solution (Given : molecular mass of oxalic acid = 126)?

1.275 g

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5.575 g

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1.575 g

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1.550 g

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Solution

The correct option is D 1.575 g
n. factor for $H_{2} C_{2} O_{4}$ =2
Equivalent weight = $\frac{M}{2}$
Normality = $\frac{w e i g h t \times 1000}{e q u i v a l e n t w e i g h t \times v o l u m e (i n m L)}$
0.1= $\frac{w e i g h t \times 1000}{(\frac{126}{2}) \times 250}$
Therefore, weight = 1.575g

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