Question

# What are the correct oxidation state, coordination number, configuration, magnetic character and magnetic moment of $$K_4[Mn(CN)_6]$$?

A
O.S +6, - C.N 6, - Configuration t52g, - Magnetic Charater Diamagnetic, - Magentic Moment 0
B
O.S +4, - C.N 6, - Configuration t52ge1g, - Magnetic Charater Paramagnetic, - Magentic Moment 1.732 B.M
C
O.S +2, - C.N 6, - Configuration t52g, - Magnetic Charater Paramagnetic, - Magentic Moment 1.732 B.M
D
O.S +4, - C.N 6, - Configuration t52ge2g, - Magnetic Charater Diamagnetic, - Magentic Moment 0

Solution

## The correct option is C O.S +2, - C.N 6, - Configuration $$t_{2g}^{5}$$, - Magnetic Charater Paramagnetic, - Magentic Moment 1.732 B.M$$K_4[Mn(CN)_6]\Rightarrow [Mn(CN)_6]^{4-}$$$$n-6(1)=-4$$$$n=6-4=2$$$$n=2$$so, $$O.S=+2$$$$Mn^{2+}\Rightarrow [Ar]3d^5$$As $$CN^-$$ is strong field ligand Pairing occur in $$t_{2g}$$$$=E.C=t_{2g}^5 e_{g}^o$$The co-ordination number $$=6$$It has i unpaired electrons So paramagnetic.Magneic Moment $$=\sqrt{1(1+2)}=\sqrt{3}=1.732B.M$$Chemistry

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