What are the values of the orbital angular momentum of an electron in the orbitals $1 s,$ $3 s,$ $3 d$ and $2 p$ ?

0, 0, \sqrt{6} \frac{h}{π 2}, \sqrt{2} \frac{h}{π 2}

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1, 1, \sqrt{4} \frac{h}{π 2}, \sqrt{2} \frac{h}{π 2}

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0, 1, \sqrt{6} \frac{h}{π 2}, \sqrt{3} \frac{h}{π 2}

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0, 0, \sqrt{20} \frac{h}{π 2}, \sqrt{6} \frac{h}{π 2}

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Solution

The correct option is A $0, 0, \sqrt{6} \frac{h}{π 2}, \sqrt{2} \frac{h}{π 2}$
Orbital angular momentum of an electron = $\sqrt{l (l + 1)} h$
$l = 0 ⟹ s o r b i t a l$
For 1s, 3s it is $0$
$l = 1 ⟹ p o r b i t a l$
For 2p it is $\sqrt{2} h$
$l = 2 ⟹ d o r b i t a l$
For 3d it is $\sqrt{6} h$

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