Question

What can be inferred from the following equation?

$N{a}_{2}S{O}_4\left(aq\right)+BaC{l}_2\left(aq\right)\to BaS{O}_4\left(s\right)+2NaCl\left(aq\right)$

(i) It is a double displacement reaction.

(ii) It is a precipitation reaction.

(iii) It is a decomposition reaction.

(iv) $BaS{O}_4$ is soluble in water

(v) $BaS{O}_4$ is precipitate.

(vi) $NaCl$ dissolves in water.

• A. (i),(ii), (v), (vi).
• B. (i),(ii), (iv), (vi).
• C. (ii),(iii), (iv), (vi).
• D. (i),(iii), (v), (vi).

Answer 1

Answer: (A)

(i),(ii), (v), (vi).

$N{a}_{2}S{O}_4\left(aq\right)+BaC{l}_2\left(aq\right)\to BaS{O}_4\left(s\right)+2NaCl\left(aq\right)$

In above reaction, $N{a}^{+}$ and $B{a}^{2+}$ ions are exchanged between the reactants, hence it is a displacement reaction.

The product $BaS{O}_4$ is not soluble in water, hence is a precipitate. This reaction is also called precipitation reaction due to the formation of a precipitate. $NaCl$ dissolves in water.