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B
Ajmer Faizabad
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C
Amritsar Faridabad
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D
Ajmer Faridabad
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E
Cannot be determined
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Solution
The correct option is C Ajmer Faridabad Observe all numbers are multiple of 3. Number: (Number of letters in word –1)×3 Observe 4 symbols are used and there are words ending in 4 letters only u,r,d,i So u is represented by #, ris represented by @, dis represented by %, iis represented by $. Alphabet: (first letter of word –2). If the first letter represents number≤13 i.e.(26/2) then alphabet written at start, but if first letter represents number > 13 (26/2) then alphabet written at end So Jammu will be coded as: J=10 which is≤13, 10−2=8 which is H, last letter uis represented by #, and number of letters in 5 so (5−1)×3=12 So H#12 Puriwill be coded as: P=16 which is >13, 16−2=14 which is N, last letter iis represented by,andnumberoflettersinPuriis4so(4-1) \times 3 = 9$ So 9N$
Following the above logic
In Y@12, first alphabet of our answer is A, last alphabet of answer is R and total no. of alphabets in the word are 5, which is satisfied by option D.
In D%24, first alphabet of our answer is F, last alphabet of answer is D and total no. of alphabets in the word are 9, Faridabad satisfies the above conditions.