What has to be added to x2+3x−8 to get x2+x+6?
3 - 8
- 2x + 14
x + 6
2x + 14
(x2+x+6) - (x2+3x−8) = x2+x+6 - x2−3x+8 = - 2x + 14 So, - 2x + 14 is to added to (x2+3x−8) to get (x2+x+6).
What should be added to x2+3x−8 to get x2+x+6?
What must be added to(x3+3x−8) to get (3x3+x2+6)?