What has to be added to $x^{2} + 3 x - 8$ to get $x^{2} + x + 6$ ?

3 - 8

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- 2x + 14

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x + 6

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2x + 14

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Solution

The correct option is B
- 2x + 14

( $x^{2} + x + 6)$ - ( $x^{2} + 3 x - 8)$
= $x^{2} + x + 6$ - $x^{2} - 3 x + 8$
= - 2x + 14
So, - 2x + 14 is to added to ( $x^{2} + 3 x - 8)$ to get ( $x^{2} + x + 6)$ .

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