Question

What is likely to be orbit number for a circular orbit of diameter 20 nm of the hydrogen atom if we assume Bohr orbit to be the same as that represented by the principal quantum number?

• A. 10
• B. 14
• C. 12
• D. 16

Answer 1

The correct option is B 14

The radius of Bohr's orbit is 10 nm

also, radius of Bohr's orbit is given by $\frac{0.0529\times n^2}{z}nm$ as $z=1$,

$\therefore r=0.0529n^2$ nm

equating the above two, we have,

10 nm = (0.0529 n${}^2$) nm

n${}^2$= 189.03

n = 14

Hence, the correct option is $B$