Question

What is magnification in the below diagram?

Given OA = $10cm$ and O’A’ = $2cm$.

• A. $5$
• B. $-2$
• C. $-0.2$
• D. $-10$

Answer 1

The correct option is C $-0.2$


Given:
Height of the image, $h_i=-2cm$ (inverted image);
Height of the object, $h_o=10cm$ (erect object);
Magnification $\left(m\right)=\frac{\text{height of image}}{\text{height of object}}$ = $\frac{h_i}{h_o}$
$\Rightarrow \frac{-2}{10}=\frac{-1}{5}=-0.2$.
The negative sign in magnification shows that the image formed is real.