Question

What is magnification in the below diagram?

Given, OA = $10\text{cm}$ and O’A’ = $2\text{cm}$.

• A. $5$
• B. $-2$
• C. $-0.2$
• D. $-10$

Answer 1

The correct option is C $-0.2$


Given:
Height of the image, $h_i=-2\text{cm}$ (inverted image)
Height of the object, $h_o=10\text{cm}$ (erect object)
Magnification $\left(m\right)=\frac{\text{Height of image}}{\text{Height of object}}$ = $\frac{h_i}{h_o}$
$\Rightarrow \frac{-2}{10}=\frac{-1}{5}=-0.2$

The negative sign in magnification shows that the image formed is inverted.