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Question

What is the acceleration due to gravity on the top of Mount Everest? Mount Everest is the highest mountain peak of the world at the height of 8848 m. The value at sea level is $$ 9.80 m/s^2 $$


Solution

Given 
h= 8848m

The value of acceleration of gravity at sea level is $$9.80m/s^2$$
Acceleration due to gravity at any point is given by :
$$g'=\dfrac {GM}{(R+h)^2}$$
Let $$g′$$ be the acceleration due to the gravity on the  Mount Everest.
as $$h<<<R$$
$$g'=g\left[ 1-\dfrac { 2h }{ R }  \right] \\ =9.80\left[ 1-\dfrac { 2\times 8848 }{ 6400000 }  \right] \\ =9.80\left[ 1-0.00276 \right] \\ =9.8×0.99724\\ =9.773m/s^{ 2 }$$

Physics

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