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Question

What is the angular momentum of an electron in Bohr's hydrogen atom whose energy is 3.4 eV?

A
L=hπ
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B
L=4hπ
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C
L=3hπ
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D
L=5hπ
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Solution

The correct option is A L=hπ
First, we need to identify the quantum number of the energy level.
As E=13.6n2, we have
3.4=13.6n2 or n=2
The angular momentum quantization gives, L=mvr=nh2π
Substituting n=2, we get L=2h2π=hπ

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