Question

What is the angular momentum of an electron in Bohr’s hydrogen atom whose energy is - 0.544 eV.

• A. $\frac{h}{\pi }$
• B. $\frac{2h}{\pi }$
• C. $\frac{5h}{2\pi }$
• D. $\frac{7h}{2\pi }$

Answer 1

The correct option is C $\frac{5h}{2\pi }$

By using $E=-\frac{13.6}{n^2}eV$ $\left(for{H}_{2}atom\right)$
$\Rightarrow -0.544=-\frac{13.6}{n^2}\Rightarrow n^2=25\Rightarrow n=5$
$\therefore$ momentum $=n\frac{h}{2\pi }=\frac{5h}{2\pi }$