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Question

What is the area of the rhombus ABCD below if AC=12 cm and BE= 8 cm?


A

384 cm2

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B

192 cm2

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C

48 cm2

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D

96 cm2

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Solution

The correct option is D

96 cm2


The diagonals of a rhombus bisect each other. Therefore, in the given figure:

BE=DE

BD=2×BE

BD=2×8=16 cm

Area of a rhombus equals half the product of length of the two diagonals.

Area of ABCD = 12×AC×BD
Area of ABCD= 12×12×16=96 cm2.


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