What is the base perimeter of a rectangular prism which is formed by joining two identical right triangular prisms? It is given that each right triangle has a height of 2 m and base 4 m.

12 m

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13 m

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11 m

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17 m

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Solution

The correct option is A
12 m

$B a s e p e r i m e t e r o f a r e c t a n g u l a r p r i s m = 2 \times (r i g h t t r i a n g l e^{'} s h e i g h t + r i g h t t r i a n g l e^{'} s b a s e)$

$\Rightarrow B a s e p e r i m e t e r o f t h e r e c t a n g u l a r p r i s m = 2 \times (2 + 4)$

$\Rightarrow B a s e p e r i m e t e r o f t h e r e c t a n g u l a r p r i s m = 2 \times 6 = 12 m$

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What is the base perimeter of a rectangular prism which is formed by joining two identical right triangular prisms? It is given that each right triangle has a height of 2 m and base 4 m.

The correct option is A 12 m Base perimeter of a rectangular prism=2×(right triangle′s height+right triangle′s base) ⇒ Base perimeter of the rectangular prism=2×(2+4) ⇒Base perimeter of the rectangular prism=2×6=12 m