    Question

# What is the current flowing through the 10 Ω resistor in the figure below? A
0.1 A
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B
0.2 A
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C
0.3 A
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D
0.4 A
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Solution

## The correct option is A 0.2 AAs the current flows from a higher potential to a lower potential, the current direction is as shown below from node 1 to node 0. If voltage at node 0 is V0 then applying Kirchoff's loop law, the current i through the 10 Ω is given by: i=10−V010 ⟹ 10−V0=10i -- (1)  Consider the currents flowing through 20 Ω and 30 Ω be i2 and i3 respectively. Applying the law similarly for nodes 2 and 3 as shown above, we will get V0−7=20i1 -- (2) V0−5=30i2 -- (3) Adding equations (1), (2) we will get 3=10i+20i1=30i1+10i2 (since i=i1+i2) 30i1+10i2=3 10i1+40i2=5 Solving, i=19110 A≈0.2 A  Suggest Corrections  1      Similar questions  Related Videos   Kirchoff's Voltage Law
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