What is the difference between the average number of male employees in all the given companies in 2006 and the average number of female employees in all the given companies in 2009?

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Solution

The correct option is A 68
The average number of male employees in 2006
$= \frac{139 + 164 + 152 + 178 + 212 + 241}{6} = \frac{1086}{6} = 181$
The average number of female employees in 2009
$= \frac{242 + 238 + 267 + 214 + 230 + 303}{6} = \frac{1494}{6} = 249$
$∴$ Required difference = 249 - 181 = 68

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What is the difference between the average number of male employees in all the given companies in 2006 and the average number of female employees in all the given companies in 2009?

The correct option is A 68The average number of male employees in 2006 =139+164+152+178+212+2416=10866=181 The average number of female employees in 2009 =242+238+267+214+230+3036=14946=249 ∴ Required difference = 249 - 181 = 68