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Question

What is the difference in perimeters of triangles ABC and ACD in the given figure ABCD? (Take 2 = 1.4 and 5 = 2.2)

 



Your Answer
A

0.8 m

Your Answer
B

0.3 m

Your Answer
C

0.6 m

Correct Answer
D

0.4 m


Solution

The correct option is D

0.4 m


ABC is a right - angled isosceles triangle.

The sides are in the ratio 1 : 1 : 2

Let the sides be x, x , 2 x

Here,  x = 2

The Length of AC =  2

                          =  2×2 = 2 m

Hence, using Pythagoras theorem we can say:

AD = 12+22 = 5 m

Perimeter of the figure ABC = AB + BC + AC 

= 2+2+2

= 1.4 + 1.4 + 2

= 4.8 m

Perimeter of the figure ACD = AC+CD+AD

= 2+1+5

= 3+ 2.2

= 5.2 m

So, the required difference in perimeters =5.2 -4.8 = 0.4 m

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