What is the equation for the equilibrium constant (Kc) for the following equilibrium reaction?
12A(g)+13B(g)⇌32C(g)
A
KC=[A]12[B]13[C]32
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B
KC=[C]32[A]2[B]2
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C
KC=[C]32[A]12[B]13
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D
KC=[C]32[A]12+[B]13
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Solution
The correct option is CKC=[C]32[A]12[B]13 The equilibrium reaction is 12A(g)+13B(g)⇌32C(g)
The equilibrium constant is the ratio of the molar concentrations of the products to the molar concentrations of the reactants. The molar concentrations are raised to appropriate powers which are the stoichiometric coefficients.
The expression for the equilibrium constant is KC=[C]32[A]12[B]13.