What is the equation of a line that passes through the point $(4, - 5)$ and is parallel to $3 x + 2 y = 12$ ?

y = - 3 x + 6

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y = \frac{3}{2} x + 1

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y = 3 x + 1

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y = \frac{- 3}{2} x + 1

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Solution

The correct option is D $y = \frac{- 3}{2} x + 1$
The slope of the given line is -3/2
Parallels have equal slopes
The new line y + 5 = (-3/2) (x - 4)
y + 5 = (-3/2)x + 6
y = (-3/2)x + 1

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Similar questions

2 x + y + 1 = 0

3 x - y + 4 = 0

3 x - 2 y = 0

Equation of the line passing through (1, 2) and parallel to the line $y = 3 x - 1$ is .

2 x + y = 1

3 x + 2 y = 5

\frac{3 x - y + 1}{3} = \frac{2 x + y + 2}{5} = \frac{3 x + 2 y + 1}{6}

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