What is the equivalent mass of HCl in the given reaction- 2 KMnO 4-16 HCl - 2 KCl -2 MnCl 2-5 Cl 2-8 H 2 OA- 44-2B- 36-5C- 58-4D- none of these

The correct option is C 58.4As only 10 moles of Cl^ ions undergoes oxidation, n factor of HCl will be = 1016 = 58 Equivalent weight of HCl = Molar Massn f ...

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Standard XII

Chemistry

Balancing Redox Equations

What is the e...

Question

What is the equivalent mass of HCl in the given reaction?

$2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O$

44.2

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36.5

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58.4

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none of these

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Solution

The correct option is C 58.4
As only 16 moles of $C l^{-}$ ions undergoes oxidation,( $5 C l_{2}$ is product formed)
n - factor of HCl will be $= \frac{10}{16} = \frac{5}{8}$ (N-factor of an acid is its basicity, in 16 moles of HCl, 10 moles of HCl is consumed)
$Equivalent weight of HCl = \frac{Molar Mass}{n - factor}$

$Equivalent weight of HCl = \frac{36.5}{(\frac{5}{8})} = \frac{8 \times 36.5}{5} = 58.4$

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Similar questions

Q. What is the equivalent mass of HCl in the given reaction?

2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O

Q. For the balanced redox reaction:

2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O

Calculate the number of gram equivalents of

H C l

58.4 g

H C l

is taken.

Q. In the following reaction:

2 K M n O_{4} + 16 H C l \to 5 C l_{2} + 2 M n C l_{2} + 2 K C l + 8 H_{2} O

, the reduction product is :

Q. For the balanced redox reaction:

2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O

Calculate the number of gram equivalents of

H C l

58.4 g

H C l

is taken.

Q. Sodium chlorate,

N a C l O_{3}

, can be prepared by the following series of reactions.

2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 8 H_{2} O + 5 C l_{2}

6 C l_{2} + 6 C a {(O H)}_{2} \to C a {(C l O_{3})}_{2} + 5 C a C l_{2} + 6 H_{2 O}

C a {(C l O_{3})}_{2} + N a_{2} S O_{4} \to C a S O_{4} + 2 N a C l O_{3}

What mass of

N a C l O_{3}

can be prepared from

100

ml of concentrated HCl (density

1.28

g/ml and

36.5

% by mass)?

Assume all other substances are present in excess amounts.

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What is the equivalent mass of HCl in the given reaction? 2KMnO4+16 HCl→2KCl+2MnCl2+5Cl2+8H2O

What is the equivalent mass of HCl in the given reaction?

$2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O$